Question

A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly at a rate of 1.2 m/s2 for 4.5 seconds. It then continues at a constant speed for 12.1 seconds, before getting tired and slowing down with constant acceleration coming to rest 87 meters from where it started. The tortoise accelerates uniformly for the entire distance, finally catching the hare just as the hare comes to a stop. 1) How fast is the hare going 3.6 seconds after it starts

Answer 1

`v=4.32m/s`

Step-by-step explanation:

From the question we are told that:

Accelerates at rate of
`1.2m/s^2`

Acceleration time
`t_a=4.5secs`

Velocity time 1
`t_(v1)=12.1secs`

Deceleration distance
`d_a=87meters`

Generally the Newton's equation for motion is mathematically given by

`V=at`

`v=(1.2)3.6`

`v=4.32m/s`