Question

As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion

Answer 1

`A_[avg}=1.81m/s`

Step-by-step explanation:

From the question we are told that:

North Movement

Velocity
`V=2.8`

Time
`t=46 minuites`

South movement

Distance
`d=3,132`

Time
`t'= 54 minutes`

Generally the equation for Average Velocity is mathematically given by

`A_[avg}\]frac{Total distance}{Total time}`

Where

Total distance d_t

`d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled`

`d_t=(2.8*46*60)+(3132)`

`d_t=10860`

An

Total Time

`T=(46+54)60`

`T=6000`

Therefore

`A_[avg}=(d_t)/(T)`

`A_[avg}=(10860)/(6000)`

`A_[avg}=1.81m/s`