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If the spin rate of the CD is 580 rpm what distance is traveled by the piece of dust (in radians) in 2.9 mins

User Nilo Alan
by
8.0k points

1 Answer

5 votes

Answer:


d=10568.76rads

Explanation:

From the question we are told that:

Angular Velocity
\omega=580rpm=>60.74rads/sec

Time
t=2.9mins=>174sec

Generally the equation for distance d is mathematically given by


d=\omega*t


d=60.74*174


d=10568.76rads

User Chadwick Meyer
by
8.7k points
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