Question

The slope, m, of a linear equation can be found using the formula m = v2 - v1/x2 - x1 , where the x- and the y-values come from two ordered pairs, and (x1,y1) and (x2,y2).

What is an equivalent equation solved for y2?

A. y2 = mx2 - x1 + y1

B. y2 = mx2 - x1 - y1

C. y2 = m(x2 - x1) + y1

D. y2 = m(x2 - x1) - y1

HELP PLEASE!!!!!

Answer 1

y2 = m(x2-x1)+y1

Explanation:

Given the expression;

m = y2-y1/x2-x1

Making y2 the subject of the formula

Cross multiply

m(x2-x1) = y2-y1

Add y1 to both sides

m(x2-x1)+y1 = y2-y1+y1

m(x2-x1)+y1 = y2

Hence y2 = m(x2-x1)+y1