Given:
Principal = $54,000
Time = 9 years
Rate of compound interest = 12% per annum.
To find:
The compound interest.
Solution:
The formula for amount is:
![A=P\left(1+(r)/(n)\right)^(nt)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1yi3t2vfymj1yef0esmyqtznndeu9rq3fw.png)
Where, P is principal, r is the rate of interest in decimal, n is the number of time interest compounded and t is the number of years.
The interest is compounded annually, so
.
Substituting
in the above formula, we get
![A=54000\left(1+(0.12)/(1)\right)^(1(9))](https://img.qammunity.org/2022/formulas/mathematics/high-school/ty3r6m7v0ybhmtsxnpqurb3fpujzxacr9b.png)
![A=54000\left(1.12\right)^(9)](https://img.qammunity.org/2022/formulas/mathematics/high-school/hgdt6iepidc02evf7tp3lyicu1hcxj02zx.png)
![A=149746.252902](https://img.qammunity.org/2022/formulas/mathematics/high-school/9ne5hislbspihm7wio88fv1v90ktdzqkwl.png)
![A\approx 149746.25](https://img.qammunity.org/2022/formulas/mathematics/high-school/uu5t8rdvshl71r8e0eelu4p3fmuiirobui.png)
The amount after 9 years is $149746.25.
Now, the compound interest is:
![C.I.=A-P](https://img.qammunity.org/2022/formulas/mathematics/high-school/hcha9t87e3bpd1xsxp4nvs1zehaltuew1c.png)
Where, C.I. is compound interest, A is amount and P is principal.
![C.I.=149746.25-54000](https://img.qammunity.org/2022/formulas/mathematics/high-school/y7p48p0c1mfuuodkarnfgt1f9dv45viatj.png)
![C.I.=95746.25](https://img.qammunity.org/2022/formulas/mathematics/high-school/dwm7ialb8greb0y7zw23o8mxgulei8p5vl.png)
Therefore, the compound interest is $95746.25.