Question

2.) Find the zeros of the quadratic function y = x2 – 3x + 2 by factoring method. ​

Answer 1

The zeros are 1 and 2

Explanation:

Given

`y =x^2 - 3x + 2`

Required

The zeros

`y =x^2 - 3x + 2`

Expand

`y =x^2 - 2x-x + 2`

Factorize

`y =x(x - 2)-1(x - 2)`

Factor out x - 2

`y =(x - 1)(x - 2)`

Set to 0

`(x - 1)(x - 2)=0`

Solve for x

`x - 1 = 0 \to x =1`

`x - 2 = 0 \to x =2`

Hence, the zeros are 1 and 2