Question

If a force of 50 N stretches a spring 0.40 m, what is the spring constant?

Answer 1

The spring constant = 125 N/m

Step-by-step explanation:

Given that :

Force = 50 N

distance (x) = 0.40 m

Recall that, From Hooke's law

Force = kx

where;

k = spring constant.

∴

50 N = k × 0.40 m

k = 50 N/0.40m

k = 125 N/m