Question

calculate to e amount of ammonium chloride needed to produce 200L of hydrogen chloride (HCL) gas at 1.22atm and 573k. NH4Cl ➡️NH3+HCl​

Answer 1

277.8g of NH4Cl are needed

Step-by-step explanation:

Based on the reaction, 1mol of NH4Cl reacts producing 1 mole of HCl. To solve this question we must find the moles of HCl using ideal gas law. These moles = Moles NH4Cl:

Moles HCl = Moles NH4Cl

PV = nRT; PV/RT = n

Where P is pressure = 1.22atm,

V is volume = 200L,

R is gas constant = 0.082atmL/molK

And T is absolute temperature = 573K

Replacing:

1.22atm*200L/0.082atmL/molK*573K = n

n = 5.193 moles HCl = Moles NH4Cl

Mass NH4Cl -Molar mass: 53.491g/mol-

5.193 moles * (53.491g / mol) =

277.8g of NH4Cl are needed