Question

Simplify (sin^2 0+cos^2 0) (sin 0+cos 0)
Can someone help? I don’t understand.

Answer 1

C

Explanation:

To start this problem off, we should know an important trig rule:

`\sin^2(\theta)+\cos^2(\theta)=1`

From here, it is simple:

`(\sin^2(\theta)+\cos^2(\theta))(\sin(\theta)+\cos(\theta))=\\1(\sin(\theta)+\cos(\theta))=\\\sin(\theta)+\cos(\theta)`

C

I hope this helps! Let me know if you have any questions :)

Answer 2

C)
`sin\theta+cos\theta`

Explanation:

`(sin^2\theta+cos^2\theta)(sin\theta+cos\theta)`

`sin\theta+cos\theta`

Recall the Pythagorean Trigonometric Identity where
`sin^2\theta+cos^2\theta=1`, so
`1(sin\theta+cos\theta)=sin\theta+cos\theta`