Log (sqrt(xy))/z is equal to a) 1/2 logx + 1/2 logy - logz b) 1/2 logx + logy - logz c) 1/2 (logx + logy - logz) d) 1/2 log xy/ logz

asked Mar 9, 2022 101k views

5 votes

Log (sqrt(xy))/z is equal to

a) 1/2 logx + 1/2 logy - logz
b) 1/2 logx + logy - logz
c) 1/2 (logx + logy - logz)
d) 1/2 log xy/ logz

by Jeffz

3.5k points

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5 votes

Answer:

A)
(1)/(2)log(x)+(1)/(2)log( y)-log(z)

Explanation:

log(√(xy))/(z)

log√(xy)-log(z)

log(xy)^(1)/(2)-log(z)

(1)/(2)log(xy)-log(z)

(1)/(2)(log(x)+log(y))-log(z)

(1)/(2)log(x)+(1)/(2)log( y)-log(z)

Therefore, A is correct

Arwed Mett answered Mar 13, 2022

3.2k points

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