Question

Aubrey filled her pool 0.9 of the way with water. Water evaporated from the pool at a rate of 7.5ft ^ 3 per day.

Answer 1

Answer: hello your question lacks vital data hence I will provide you with a general equation within the scope of your question

answer :

General equation = ( Stiver and Mackay or EPA ) evaporation equations

E =
`(PAW)/(T +459.67)` or E =
`(7.4PA(0.447W)^(0.8) )/(T + 459.67)`

Explanation:

Given data

volume of water in pool = 0.9 i.e. 90% full

rate of evaporation = 7.5ft^3 per day = 56.1039 gallons / day

Assumption :

Volume of pool = 16,000 gallons

In order to resolve the missing part of the problem apply the equation below

E =
`(PAW)/(T +459.67)` or E =
`(7.4PA(0.447W)^(0.8) )/(T + 459.67)`

where : E = Evaporation rate , P = water's vapor pressure , A = pool surface Area , W = wind speed , T = Temperature in Fahrenheit