Question

A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.656-g sample of the mixture, the mass of precipitate collected is 1.658 g. What is the mass percentage of barium chloride in the mixture

Answer 1

`\% m=40.46\%`

Step-by-step explanation:

Hello there!

in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

`BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl`

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

`m_(BaCl_2)=1.658gBaSO_4*(1molBaSO_4)/(233.38 gBaSO_4) *(1molBaCl_2)/(1molBaSO_4)*(208.23 gBaCl_2)/(1molBaCl_2)\\\\m_(BaCl_2)=1.479gBaCl_2`

Thus, the mass percentage is calculated as shown below:

`\% m=(1.479g)/(3.656g)*100 \% \\\\\% m=40.46\%`

Regards!