Question

Write the recurring decimal 0.25 (with just the 5 recurring) as an exact fraction.

Thank you! ​

Answer 1

23/90

Explanation:

Create a variable called "x" with a value of 0.2555 repeating.

10x would be equal to 2.555 repeating.

Calculate 10x - x using these numbers; 2.555 repeating minus 0.2555 repeating is 2.3 (the repeating fives subtract and cancel out). 2.3 is equal to 9x, so to find x, we write the fraction 2.3/9. To get rid of the decimal in the numerator, we multiply both the numerator and the denominator by 10: this gives 23/90. 23 is a prime number, so we know this fraction cannot be simplified further.