Question

For a reaction, Delta * H ^ 0 = - 75KJ / m * o * l and triangle S^ 0 =-0.081KJ/(K* mol) . At what temperatures is this reaction spontaneous?

Answer 1

At temperatures below 924.93K.

Step-by-step explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy of reaction:

`\Delta G=\Delta H-T\Delta S`

Now, for us to determine the correct temperature range, we must make ΔG=0 and solve for T:

`T=(\Delta H)/(\Delta S) =(-75kJ/mol)/(-0.081kJ/mol-K)\\\\T=925.93K`

Thus at temperatures below 925.93 K we will have an spontaneous reaction (ΔG<0).

Regards!