Question

Simplify this log problem:
3log3(9)

Answer 1

3*log3(3^2) = 3*2*log3(3)= 3*2*1=6

Answer 2

6

Explanation:

3log3(9)

Rewriting 9 as 3^2

3log3(3^2)

Using log a^b = b loga

3 * 2log3(3)

We know log 3 (3) =1

3*2 (1)

6