Question

4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)​

Answer 1

• Mass=268kg=m
• P.E=50000J
• acceleration due to gravity=g=10m/s^2
• Height be h

`\\ \sf\longmapsto PE=mgh`

`\\ \sf\longmapsto 50000=268(10)h`

`\\ \sf\longmapsto 50000=2680h`

`\\ \sf\longmapsto h=(50000)/(2680)`

`\\ \sf\longmapsto h=18.65m`

Answer 2

h = 18.65 m

Step-by-step explanation:

Given that,

The mass of a boulder, m = 268 kg

The potential energy at the hill, E = 50,000 J

We need to find the height of the hill.

We know that, the potential energy of an object is given by :

E = mgh

Where

h is the height of the hill

So,

`h=(E)/(mg)\\\\h=(50000)/(268* 10)\\\\h=18.65\ m`

So, the height of the hill is 18.65 m.