Question

What volume of O2 at STP is required to oxidize 8.0 L of NO at STP to NO2? What volume of NO2 is produced at STP?

Answer 1

The balanced equation of the reaction is:

`O_2 + 2 NO` ⇒
`2 NO_2`

Every gas occupied 24 L in one mole in r.t.p. according to the equation:

`24 * n = V`

8/24=0.333 mol

2 moles of NO makes 2 moles of
`NO_2\\` so

0.333*24=8L