Question

A stock solution of calcium sulfate, CaSO4 has a concentration of 3.00 M. The volume of this solution is 150 mL. What volume of a 1.25 M solution could be made from the stock solution?

Answer 1

Answer: The volume of stock solution needed is 62.5 mL

Step-by-step explanation:

A solution consists of solute and solvent. A solute is defined as the component that is present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

To calculate the volume of stock solution needed, the formula used is:

`C_1V_1=C_2V_2` ....(1)

where,

`C_1\text{ and }V_1` are the concentration and volume of stock solution.

`C_2\text{ and }V_2` are the concentration and volume of diluted solution.

We are given:

`C_1=3.00M\\V_1=?mL\\C_2=1.25M\\V_2=150mL`

Putting values in equation 1, we get:

`3.00* V_1=1.25* 150\\\\V_1=(1.25* 150)/(3.00)\\\\V_1=62.5mL`

Hence, the volume of stock solution needed is 62.5 mL