81.1k views
1 vote
I keep getting the wrong answer and have no idea what to do

I keep getting the wrong answer and have no idea what to do-example-1
User Chadams
by
7.1k points

1 Answer

4 votes

Answer:

[C] 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

Algebra I

  • Terms/Coefficients
  • Functions
  • Function Notation

Calculus

Limits

Derivatives

Definition of a Derivative:
\displaystyle f'(x)= \lim_(h \to 0) (f(x + h) - f(x))/(h)

Explanation:

Step 1: Define

Identify


\displaystyle\displaystyle g(x) = \lim_(h \to 0) (f(x + h) - f(x))/(h)


\displaystyle f(x) = (3)/(5x^4 + 3)


\displaystyle g(0)

Step 2: Differentiate

  1. Substitute in x [Function g(x)]:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (f(0 + h) - f(0))/(h)
  2. Substitute in function f(x) [Function g(x)]:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) ((3)/(5(0 + h)^4 + 3) - (3)/(5(0)^4 + 3))/(h)
  3. Simplify:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) ((3)/(5h^4 + 3) - 1)/(h)
  4. Rewrite:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (3)/(h(5h^4 + 3)) - (1)/(h)
  5. Rewrite:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (3)/(h(5h^4 + 3)) - (5h^4 + 3)/(h(5h^4 + 3))
  6. [Subtraction] Combine like terms:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (3 - 5h^4 + 3)/(h(5h^4 + 3))
  7. [Addition] Simplify:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (-5h^4 + 6)/(h(5h^4 + 3))
  8. [Distributive Property] Distribute h:
    \displaystyle\displaystyle g(0) = \lim_(h \to 0) (-5h^4 + 6)/(5h^5 + 3h)
  9. Evaluate limit [Power Method]:
    \displaystyle\displaystyle g(0) = 0

Since the bottom polynomial has a higher degree than the top polynomial, the bottom polynomial will increase faster.

∴ If the bottom is approaching a bigger value, the fraction gets smaller and smaller, approaching 0.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

User Vishal Yadav
by
8.0k points