1 Answer

Italankin · Answer 1 · 2022-03-07T04:03:58+0000

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

$\boxed{ \large \boxed{h {}^(2) = {b}^(2) + p{}^(2) }}$

note :

let's solve for " y² " first ( square of other missing side )

$➢ \: \: {y}^(2) = {8}^(2) + 3 {}^(2)$

$➢ \: \: {y}^(2) = 64 + 9$

$➢ \: \: {y}^(2) = 73$

now let's solve for " x " , by using pythagorous theorem

$➢ \: \: {x}^(2) = {y}^(2) + {6}^(2)$

$➢ \: \: {x}^(2) = 73 + 36$

$➢ \: \:x {}^(2) = 109$

$➢ \: \: x = √(109)$

Approximate :

$➢ \: \: 10.44 \: \: units$

$\mathrm{✌TeeNForeveR✌}$

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