Question

Two species of birds are being compared. Species A can fly 18.9 miles in 42 minutes, while species B can fly 20.3 miles in 58 minutes. Which species is slower, and at what speed can it fly?

A Species A is slower, and it can fly 0.35 miles per minute.
B Species A is slower, and it can fly 0.45 miles per minute.
C Species B is slower, and it can fly 0.35 miles per minute.
D Species B is slower, and it can fly 0.45 miles per minute.
100 POINTS

Answer 1

Option C .

Explanation:

Here it is given that there are two species of birds which fly at different rates.

• Species A can fly 18.9 miles in 42min .
• Species B can fly 20.3miles in 59min .

We can use the formula here ,

`\longrightarrow \red{ Speed =\frac{Distance} {Time} }`

For Species A :-

Substitute the respective values in stated formula ,

`\longrightarrow v_A = (18.9\ miles)/(42min)\\`

Simplify ,

`\longrightarrow v_A = 0.45\ miles / min`

For species B :-

Substitute the respective values in stated formula,

`\longrightarrow v_B =(20.3\ miles)/(58min)\\`

`\longrightarrow v_B = 0.35\ miles / min`

Therefore from above calculations we can say that ,

`\underline{\underline{ v_A > v_B }}`

Species B is slower and it can fly 0.35miles/minute .