Question

A helium tank has a volume of 13.0 L at a pressure of 26.5 atm. What is

the volume of the same amount of helium at a pressure of 1.25 atm?

Answer 1

Answer: 275.6 L

Explanation: We use Boyle's Law to solve this.

The initial pressure (P1) is 26.5, the initial volume (P1) is 13.0 L
`344.5/1.25`, and the final pressure (P2) is 1.25. Using Boyle's Law, we plug in the values into the equation.

P1V1=P2V2

(26.5 atm)(13.0 L) = (1.25 atm) V2

As a regular equation, we solve for V2.

344.5 atm/L= (1.25 atm) V2

344.5 atm/L / 1.25 atm = V2

275.6 = V2

The atm value cancelled out and we are just left with the L value.