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5 votes
9r^6/ 5r^3g^2, 5n^5c^-6 times 2n^-5c^3, and 9g^-4yA^4/3g^6y^-2 using properties of exponents, all this for 10 points

1 Answer

5 votes

Answer:

Explanation:

5n⁵c⁻⁵ * 2n⁻⁵c³ = (5*2)*n⁵⁺⁽⁻⁵⁾ * c⁻⁶⁺³

=10*n° *c⁻³

= 10c⁻³ (n° = 1}


a^(m)*a^(n)=a^(m+n)\\\\(a^(m))/(a^(n))=a^(m-n)\\\\\\(9r^(6))/(5r^(3)g^(2))=(9)/(5g^(2))*r^(6-3)\\\\=(9r^(3))/(5g^(2))\\\\\\\\(9g^(-4)y^(4))/(3g^(6)y^(-2))=(9)/(3)*g^(-4-6)*y^(4-(-2))\\\\=3*g^(-10)*y^(4+2)\\\\=3g^(-10)*y^(6)\\\\=(3y^(6))/(g^(10))

User Gerard Simpson
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