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Tìm căn bậc hai của số phức z=1+i√3

User Muzuiget
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1 Answer

6 votes

Write z in polar form:

z = 1 + √3 i = 2 exp(i π/3)

Taking the square root gives two possible complex numbers,

z = √2 exp(i (π/3 + 2)/2)

with k = 0 and k = 1, so that

z = √2 exp(i π/6) = √(3/2) + √(1/2) i

and

z = √2 exp(i 7π/6) = -√(3/2) - √(1/2) i

User Aneesh Narayanan
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