Question

Một mol khí đang ở điều kiện tiêu chuẩn thì bị nén váo một bình 5 lít. Nhiệt độ khí trong bình là 770 C. Tính áp suất khí?

Answer 1

To find the pressure of 1 mol of gas in a 5 L vessel at 77°C, convert the temperature to Kelvin and use the ideal gas law (PV = nRT). The calculated pressure is approximately 5.785 atm.

Step-by-step explanation:

To calculate the pressure of 1 mol of gas compressed into a 5 L vessel at 77°C, we can use the ideal gas law, which is expressed as PV = nRT. Here, P is the pressure we want to find, V is the volume of the gas (5 L), n is the number of moles (1 mol), R is the ideal gas constant (0.08206 L-atm/mol-K), and T is the temperature in Kelvin.

First, we need to convert the Celsius temperature to Kelvin:
T(K) = 77°C + 273.15 = 350.15 K.

Then we can plug in the values into the ideal gas law and solve for P:

PV = nRT

P = (nRT) / V

P = (1 mol * 0.08206 L-atm/mol-K * 350.15 K) / 5 L

P = 5.785 atm

Therefore, the pressure of the gas in the 5 L vessel at 77°C is approximately 5.785 atm.

Answer 2

Đáp án:

p=5,74atm

Giải thích các bước giải:

áp suất khí là:

pV=nRT⇒p=nRTV=1.0,082.(77+273)5=5,74atmpV=nRT⇒p=nRTV=1.0,082.(77+273)5=5,74atm

p=5,74atm

Giải thích các bước giải:

áp suất khí là:

pV=nRT⇒p=nRTV=1.0,082.(77+273)5=5,74atmpV=nRT⇒p=nRTV=1.0,082.(77+273)5=5,74atm