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PLEASE HELP ME WITH THIS ONE QUESTION

How many combinations with repetition are allowed if n = 6 and r = 3?

A) 27
B) 20
C) 18
D) 56

User Cjrieck
by
7.4k points

1 Answer

3 votes

Answer:

D. 56

Explanation:

The general solution for the number of combinations with repetition is represented by the following expression:


x = ((n + r - 1)!)/(r!\cdot (n-1)!) (1)

Where:


n - Total number of elements.


r - Number of the sample.

If we know that
n = 6 and
r = 3, then the number of combinations with repetition:


x = ((6+3-1)!)/(3!\cdot (6-1)!)


x = 56

Hence, correct answer is D.

User Kvance
by
8.0k points

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