Given:
Principal value = $2300
Rate of interest = 14% compounded continuously.
To find:
The time taken by Brad's investment to triple.
Solution:
The formula for amount after the compound interest (Continuously) is:
![A=Pe^(rt)](https://img.qammunity.org/2022/formulas/mathematics/high-school/82sqkrzvl0fpxzvh0rxi0p0g8lcz24clo9.png)
Where, P is the principal, r is the rate of interest in decimal and t is the time period.
Triple of Brad's investment is
![3* \$ 2300=\$ 6900](https://img.qammunity.org/2022/formulas/mathematics/high-school/53kdhyjxlmtfmx98tflvkc7saklerbwwum.png)
Substituting
, we get
![6900=2300e^(0.14t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/k5ampc3jk2o5tw2vetyq5mbwgiz5rlz5x7.png)
![(6900)/(2300)=e^(0.14t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5pzvp2iizrpc48ddxvjeblw9zmphg5wair.png)
![3=e^(0.14t)](https://img.qammunity.org/2022/formulas/mathematics/college/wvczmj2omzbjoyc0wqbe0vrunm8xkl8jye.png)
Taking natural log on both sides, we get
![\ln 3=\ln e^(0.14t)](https://img.qammunity.org/2022/formulas/mathematics/high-school/7e2kdt359i5qx82kc45mce0r535jz9s0q9.png)
![[\because \ln e^x=x]](https://img.qammunity.org/2022/formulas/mathematics/high-school/m24tge2dslw94bp9jx3y240611r7x9yr3r.png)
![(1.0986)/(0.14)=t](https://img.qammunity.org/2022/formulas/mathematics/high-school/tlx9vslwp50plfgp1uo0hyn1gr3601311m.png)
![7.84714=t](https://img.qammunity.org/2022/formulas/mathematics/high-school/rvk3k8h2k61ccosmoxyd7jmmuxwkvyyrhf.png)
After approximating the value, we get
![t\approx 7.85](https://img.qammunity.org/2022/formulas/mathematics/high-school/5ek9oj19emg99jw8o42bmh0wti3gw53lnz.png)
Therefore, Brad's investment will take 7.85 years to triple.