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5 votes
Find the equation for the

following parabola.
Vertex (-2,-4)
Focus (-4,-4)
A. (7-4)2 = -8(x-2)
B. (x+4)2 = 8(y+2)
C. (y+4)2 = 8(x+2)
D. (y+4)2 = -8(x+2)

Find the equation for the following parabola. Vertex (-2,-4) Focus (-4,-4) A. (7-4)2 = -8(x-example-1
User Chuan Ma
by
8.1k points

2 Answers

2 votes

Answer:

(y+4)2=−8(x+2)

The answer would be D.

User Sanjay Chauhan
by
7.9k points
2 votes

Answer:


(y+4)^2 = -8(x+2), option D.

Explanation:

Equation of a parabola:

The equation of a parabola has the following format:


(y - k)^2 = 4p(x-h)

In which the center is (h,k) and the focus is (h+p,k).

Vertex (-2,-4)

This means that
h = -2, k = -4

So


(y - k)^2 = 4p(x-h)


(y - (-4))^2 = 4p(x-(-2))


(y+4)^2 = 4p(x+2)

Vertex (-2,-4)

Focus (-4,-4)

-4 - (-2) = -4 + 2 = -2

So p = -2 and


(y+4)^2 = 4(-2)(x+2)


(y+4)^2 = -8(x+2), option D.

User Nihar
by
8.9k points

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