Question

Arrange the compounds in order of increasing entropy (S).

CH3OH(s)

CH3OH(l),

CH3OH(g),

CH3CH2OH(g)



CH3OH(s) > CH3OH (l) > CH3OH(g) > CH3CH2OH(g)


CH3OH(s) < CH3OH (l) < CH3OH(g) < CH3CH2OH(g)

Answer 1

The compounds CH3OH(s), CH3OH(l), CH3OH(g), CH3CH2OH(g) should be arranged in order of increasing entropy as CH3OH(s) < CH3OH (l) < CH3OH(g) < CH3CH2OH(g), considering their physical states and molecular complexity.

Step-by-step explanation:

To arrange the given compounds in order of increasing entropy (S): CH3OH(s), CH3OH(l), CH3OH(g), CH3CH2OH(g), we need to consider the physical state of the compounds and the complexity of their molecular structures. Entropy generally increases from solid to liquid to gas, and molecules with more atoms and larger volumes tend to have higher entropy because they have more microstates available.

The correct order is:

1. CH3OH(s) - Solid methanol has the lowest entropy.
2. CH3OH(l) - Liquid methanol has higher entropy than the solid.
3. CH3OH(g) - Gaseous methanol has higher entropy than the liquid.
4. CH3CH2OH(g) - Gaseous ethanol has the highest entropy of the group due to being a larger molecule than methanol, thus having more microstates.

So, the correct arrangement from lowest to highest entropy is:

CH3OH(s) < CH3OH (l) < CH3OH(g) < CH3CH2OH(g)

Answer 2

Answer: The given compounds are arranged in order of increasing entropy (S) as
`CH_(3)OH(s) < CH_(3)OH(l) < CH_(3)CH_(2)OH < CH_(3)OH(g)`

Step-by-step explanation:

The degree of randomness present in a substance is called entropy.

This means that more is the number of molecules weakly held together and rapidly moving from one place to another more will be its entropy.

In solids, the molecules are held together strongly with each other. So, they will have least entropy.

In liquids, the molecules are a little loosely held together. So, they have more entropy than a solid substance.

In gases, the molecules are held by weak forces due to which they move rapidly from one place to another. Hence, gases have high entropy as compared to solids and liquids.

Also, more is the molecular mass of a gas less will be its rate of effusion. Hence, less will be its entropy.

`Rate of effusion \propto (1)/(√(M))`

where,

M = molecular mass

Thus, we can conclude that given compounds are arranged in order of increasing entropy (S) as
`CH_(3)OH(s) < CH_(3)OH(l) < CH_(3)CH_(2)OH < CH_(3)OH(g)`