Question

A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is

Answer 1

`m=1.47* 10^(-24)\ Kg`

Step-by-step explanation:

Given that,

Charge,
`q=1.6* 10^(-19)\ C`

Revolution = 7 rev

magnetic field, B = 45 mT

Time, t = 1.29 ms

We need to find the mass of the ion. Let m be the mass. The formula for the mass in terms of time period is given by :

`m=(qBT)/(2\pi)\\\\m=(1.6* 10^(-19)* 45* 10^(-3)* 1.29* 10^(-3))/(2\pi)\\\\m=1.47* 10^(-24)\ Kg`

So, the mass of the ion is equal to
`1.47* 10^(-24)\ Kg`.