Answer:
4.08moles
Step-by-step explanation:
The balanced equation of this reaction is given as:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the above balanced equation, 1 mole of H2SO4 is needed to react with 2 moles of NaOH.
Using the formula below to calculate the number of moles in 200g of H2SO4;
mole = mass/molar mass
Molar mass of H2SO4 = 1(2) + 32 + 16(4)
= 2 + 32 + 64
= 98g/mol
number of moles = 200g ÷ 98g/mol
n = 2.04mol
Since 1 mole of H2SO4 is needed to react with 2 moles of NaOH.
Then, 2.04mol of H2SO4 is needed to react with 2.04 × 2/1 = 4.08moles of NaOH.