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Help on both please and thanks

Help on both please and thanks-example-1
User Paquita
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1 Answer

6 votes

Answer:

1. Granite

2. 535.5J

Step-by-step explanation:

1. The lower the specific heat capacity of a substance, which is the amount of heat needed to raise the temperature of a particular mass of substance by 1 °C or K, the slower the rate at which the temperature is raised.

In this question 1, the substance with the lowest specific heat capacity in J/gK is GRANITE, hence, it will raise temperature the slowest.

2. Using the formula as follows:

Q = m × c × ∆T

Where;

c = specific heat capacity

Q = amount of heat (J)

m = mass of substance

∆T = change in temperature (°C)

m = 35g, c = 0.45 J/g°C, ∆T = 54°C - 20°C = 34°C

Q = 35 × 0.45 × 34

Q = 535.5J

User Amit Modi
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5.8k points