Question

The equilibrium constant (K) for the reaction

2HCI(g) = H2(g) + Cl2(g)
is 4.17 x 10-34 at 25°C. What is the equilibrium constant for the reverse reaction at the same
temperature?
H2(g) + Cl2(g) = 2HCl(g)

Answer 1

Answer: The equilibrium constant for the reverse reaction at the same temperature is
`2.40 * 10^(33)`.

Step-by-step explanation:

The given reaction equation is as follows.

`2HCl(g) \rightleftharpoons H_(2)(g) + Cl_(2)(g)` ... (1)

It's equilibrium constant (K) value is
`4.17 * 10^(-34)`.

Also, another reaction equation is as follows.

`H_(2)(g) + Cl_(2)(g) \rightleftharpoons 2HCl(g)`

This is the reverse of equation (1). Hence, its equilibrium value is calculated as follows.

`K' = (1)/(K)\\= (1)/(4.17 * 10^(-34))\\= 2.40 * 10^(33)`

Thus, we can conclude that the equilibrium constant for the reverse reaction at the same temperature is
`2.40 * 10^(33)`.