Answer:

Explanation:
To determine the distance between any two points, we can use the distance formula. The distance formula is given by:

a is the distance between the points (-2, 3) and (-1, -1). Let (-2, 3) be (x₁, y₁) and let (-1, -1) be (x₂, y₂). Substitute and evaluate:

b is the distance between the points (2, 2) and (-1, -1). Again, we can let (2, 2) be (x₁, y₁) and (-1, -1) be (x₂, y₂). Substitute and evaluate:
