Answer:
.077
.64935
Explanation:
Let F= failure
let S= severe
we are given that
p(F|S')= .03
p(F|S)= .5
For the first question we are looking for f
we can solve for it by using the law of total probability
so in theory we want
F∩S+F∩S'
Using the conditional probability formula we can solve for the intersections
.03*.9+.5*.1= .077
2.
For this question we are looking for S|F
to solve this use bayes thereom
(or 50/77)