Question

If the length of a rectangle is four times its width and the perimeter of the rectangle is 90 yd, whats its area?

Answer 1

324 yds ^2

Explanation:

If length=l and width=w, you could write an equation to find the length and width. Then use that to find the area. L=4w. There are two of each side in the rectangle. 4w+4w+w+w=10w. 10w=90. w=9. 4w=36. L=36. 36*9=324yds^2