Answer:
![BC=9√(3)\approx15.59\text{ units}](https://img.qammunity.org/2022/formulas/mathematics/college/buhwkqoisqi9bh0ff68gcrqzp3j31p9kte.png)
Explanation:
Since Segment BOA is a diameter:
![m\angle ACB=90](https://img.qammunity.org/2022/formulas/mathematics/college/3gq5mrhs3fo1981bdktlb2qm5k04equk0y.png)
Arc Ac and Arc CB are in a ratio of two to four. Since Segment BOA is a diameter, Arc ACB measures 180°. Letting the unknown value be x, we can write that:
![2x+4x=180](https://img.qammunity.org/2022/formulas/mathematics/college/uwizbitj9c6hc82616yv12cad9jq0661zb.png)
Hence:
![x=30](https://img.qammunity.org/2022/formulas/mathematics/college/3dw0w0eptuted5s6jy4n5xab3cc5z9aawo.png)
Thus, Arc CB = 120°. By the Inscribed Angle Theorem:
![\displaystyle m\angle A=(1)/(2)\left(\stackrel{\frown}{CB}\right)=(1)/(2)\left(120)=60](https://img.qammunity.org/2022/formulas/mathematics/college/x3fb21lo9eb98koxs2om4n4fu6s8nkm35n.png)
Therefore, ΔABC is a 30-60-90 triangle. Its sides are in the ratios shown in the image below.
Since AC is opposite from the 30° triangle, let AC = a.
We are given that AC = 9. Hence, a = 9.
BC is opposite from the 60° angle and it is given by a√3. Therefore:
![BC=9√(3)\approx15.59\text{ units}](https://img.qammunity.org/2022/formulas/mathematics/college/buhwkqoisqi9bh0ff68gcrqzp3j31p9kte.png)