Question

The view factor for radiation emitted by surface 1 to surface 2 was calculated to be 0.4. The working area of surface 1 is 0.01 m2, the working area of surface 2 is 0.04 m2. What is the view factor for radiation emitted by surface 2 to surface 1?

Answer 1

The view factor for radiation emitted by surface 2 to surface 1 is 0.1

Step-by-step explanation:

Given

`F_(12) = 0.4`

`A_1 = 0.01m^2`

`A_2 = 0.04m^2`

Required

Determine
`F_(21)`

To do this, we make use of the following equivalent ratio

`A_1 * F_(12) = A_2 * F_(21)`

Make
`F_{21` the subject

`F_(21) = (A_1 * F_(12))/( A_2)`

Substitute values into the equation

`F_(21) = (0.01m^2 * 0.4)/(0.04m^2)`

`F_(21) = (0.01 * 0.4)/(0.04)`

`F_(21) = (0.004)/(0.04)`

`F_(21) = 0.1`