Question

On the grid below, draw a right triangle with vertices at E (2,2), F(2,8), and G(10,8). Find the lengths of these three sides. If necessary, round to the nearest tenth

Answer 1

To find the lengths of the sides of the right triangle with vertices at E(2,2), F(2,8), and G(10,8), you can use the distance formula. The lengths of the sides are 6 units, 10 units, and 8 units.

Step-by-step explanation:

To draw the right triangle with vertices at E (2,2), F(2,8), and G(10,8), we can plot these points on a coordinate grid and connect them to form a right triangle. The length of the sides can be found using the distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2).

Using this formula:

• Length of side EF: √((2 - 2)^2 + (8 - 2)^2) = √(0 + 36) = 6 units
• Length of side EG: √((10 - 2)^2 + (8 - 2)^2) = √(64 + 36) = √100 = 10 units
• Length of side FG: √((10 - 2)^2 + (8 - 8)^2) = √(64) = 8 units

Answer 2

The lengths of the sides are 6, 8 and 10.

Step-by-step explanation:

The vertices of a right angles triangle are E (2,2), F (2,8), and G (10,8)

The distance between the two points is

`d=\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

So, the lengths of the sides are

`EF=√((8-2)^2+(2-2)^2) = 6 \\\\FG=√((8-8)^2+(10-2)^2) = 8 \\\\GE=√((8-2)^2+(10-2)^2) = 10 \\`