Question

The drama club is running a lemonade stand to raise money for its new production. A local grocery store

donated cans of lemonade and bottles of water. Cans of lemonade sell for $2.50 each and bottles of water
sell for $1.25 each. The club needs to raise at least $600 to cover the cost of renting costumes. The students
can accept a maximum of 460 cans and bottles.
Write a system of inequalities that can be used to represent this situation.
The club sells 144 cans of lemonade. What is the least number of bottles of water that must be sold to cover
the cost of renting costumes? Justify your answer.

Answer 1

Part A

x + y ≤ 460...(1)

2.5·x + 1.25·y ≥ 600...(2)

Part B

The number of bottles of water the student must sell ≥ 192 bottles of water

Explanation:

The given parameters are;

The selling price of each can of lemonade = $2.50

The selling price of each bottle of water = $1.25

The amount of money the club needs to raise = $600

The maximum number of cans and bottles the students can accept = 460

Part A

Let 'x' represent the number of cans of lemonade the students accept, and let 'y' represent the number of bottles the student accept, the system of inequalities that can be used to represent the situation can be presented as follows;

x + y ≤ 460...(1)

2.5·x + 1.25·y ≥ 600...(2)

Part B

The number of cans of lemonade the club sells, x = 144

The number of bottles of water the student must sell to cover the cost of costumes, 'y', is given from the second inequality as follows;

2.5 × 144 + 1.25·y ≥ 600

1.25·y ≥ 600 - 2.5 × 144 = 240

1.25·y ≥ 240

y ≥ 240/1.25 = 192

y ≥ 192

The number of bottles of water the student must sell = 192 bottles of water