Question

A 10 kg box initially at rest is pulled 32 meters across a horizontal, frictionless surface by a 40 n force, as shown in the diagram below

Answer 1

The question is about finding the acceleration of a 10 kg box pulled across a frictionless surface by a 40 N force. The acceleration can be calculated using Newton's second law of motion, resulting in 4 m/s².

Step-by-step explanation:

The student's question involves determining the resulting acceleration of a 10 kg box that is pulled across a horizontal, frictionless surface by a force. This is related to Newton's second law of motion, which can be applied to find the acceleration using the formula a = F/m, where a is the acceleration, F is the force, and m is the mass of the object.

In this case, the force applied is 40 N and the mass of the box is 10 kg. Applying the formula, the acceleration would be calculated as:

a = F/m = 40 N / 10 kg = 4 m/s².

This acceleration would apply as long as the force is continuously applied and the surface remains frictionless.

Answer 2

The final velocity of the bock over the given distance is 12m/s.

Acceleration of the block

The acceleration of the block is calculated as follows;

F = ma

a = F/m

a = 40/10

a = 4 m/s²

hope this helps <3