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4 votes
A 4.88 x 10-6 C charge moves 265 m/s

parallel (at 0°) to a magnetic field of

0.0579 T. What is the magnetic force

on the charge?

User UserNeD
by
5.0k points

2 Answers

4 votes

Answer:

0 newtons

Step-by-step explanation:

When a moving charge is parallel to the magnetic field, it feels no Magnetic force at all.

Even if the Magnetic Field is 100,000,000 Tesla!

User Atlante Avila
by
5.9k points
5 votes

Answer:


F=0N

Step-by-step explanation:

From the question we are told that:

Charge
Q=4.88 x 10-6 C

Velocity
v= 265m/s

Angle
\theta =0 \textdegree

Magnetic field
B=0.0579T

Generally the equation for Force is mathematically given by


F=Q(\=v*\=B)


F=qvBsin\theta

Therefore


F=qvBsin0 \textdegree


F=0N

User LJG
by
5.4k points