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a ball is subject to two forces F1 and F2. The magnitudes of the two forces are 45.0 N and 70.0 N respectively. In the figure below you can see the free body diagram in the ball.

a ball is subject to two forces F1 and F2. The magnitudes of the two forces are 45.0 N-example-1

1 Answer

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Answer:

  • F1.x ≈ -28.93
  • F1.y ≈ 34.47
  • F2.x = 70
  • F2.y = 0
  • (F1+F2).x ≈ 41.07
  • (F1+F2).y ≈ 34.47
  • |F1+F2| ≈ 53.62
  • ∠(F1+F2) ≈ 40.0°

Step-by-step explanation:

A suitable calculator can show you the vector components and their resultant in polar or rectangular format. (See attached.) 2D vectors are conveniently treated as complex numbers, which is why the y-component values are shown as imaginary.

(The 50° angle measured from the -x axis is equivalent to 130° measured from the +x axis, which is the reference we're using here.)

If you'd like to compute the vector components by hand, they are ...

(x, y) = magnitude×(cos(angle), sin(angle))

This notation is sometimes abbreviated magnitude cis angle, a reference to the complex number form x+yi.

a ball is subject to two forces F1 and F2. The magnitudes of the two forces are 45.0 N-example-1
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