157k views
2 votes
X^2-10x=1 Solve by completing the square

2 Answers

3 votes

Answer:

-0.0990195 and 10.09902

Explanation:

To complete the square, the same value needs to be added to both sides

x^2-10x+?=1+?

To complete the square x^2-10x+25=(x-5)^2 add 25 to the expression.

x^2-10x+25=1+?

Since 25 was added to the left-side, you need to add it to the right-side as well.

x^2-10x+25=1+25

use a^2-2ab+b^2=(a-b)^2 to factor this expression.

(x-5)^2=1+25

Then add the numbers together.

(x-5)^2=26

Solve for x.

x1=-squareroot26+5

x2=squareroot26+5

therefore you have 2 solutions

x1=-squareroot26+5

=-0.0990195

and

x2=squareroot26+5

=10.09902

User Amitabha Biswas
by
8.5k points
3 votes

Answer:

x = 5±sqrt(26)

Explanation:

x^2-10x=1

Take the coefficient of x

-10

Divide by 2

-10/2 = -5

Square it

(-5)^2 = 25

Add this to both side

x^2-10x+25=1+25

(x-5)^2 = 26

Take the square root of each side

sqrt((x-5)^2) = ±sqrt(26)

x-5 = ±sqrt(26)

Add 5 to each side

x = 5±sqrt(26)

User Rishabh Singh
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories