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Given f(x)=2/5(6-x)^2 what is the value of f(6)?​
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Given f(x)=2/5(6-x)^2 what is the value of f(6)?​

Given f(x)=2/5(6-x)^2 what is the value of f(6)?​-example-1
User DataDino
by
8.1k points

1 Answer

2 votes

Answer:

0

Explanation:

f(x) = 2/5(6 - x)²

f(6) = 2/5[6 - (6)]²

f(6) = 2/5(0)²

f(6) = 0

User Fahid Mohammad
by
7.7k points
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