Question

If p(x) = 3(x^2-2)+12 what is the value of p(10)?​

Answer 1

p(10) = 306

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Functions
• Function Notation

Explanation:

Step 1: Define

Identify

p(x) = 3(x² - 2) + 12

p(10) is x = 10 for function p(x)

Step 2: Evaluate

1. Substitute in x [Function p(x)]: p(10) = 3(10² - 2) + 12
2. (Parenthesis) Evaluate exponents: p(10) = 3(100 - 2) + 12
3. (Parenthesis) Subtract: p(10) = 3(98) + 12
4. Multiply: p(10) = 294 + 12
5. Add: p(10) = 306