82.2k views
2 votes
Does anyone know how to solve this?

Does anyone know how to solve this?-example-1
User Jhunter
by
4.8k points

1 Answer

4 votes

9514 1404 393

Answer:

  • zeros: {-2, -1, 7}
  • P(x) = (x +2)(x +1)(x -7)

Explanation:

Descarte's rule of signs tells you there is 1 positive real root. The rational root theorem tells you any real roots are factors of ±14, so will be ±1, ±2, ±7, or ±14.

We note that the sum of all coefficients is negative, so +1 is not a root.

We note that the sum of coefficients of odd-degree terms is 1-19 = -18, and the sum of coefficients of even-dgree terms is -4-14 = -18. These are the same value, indicating that -1 is a root. The corresponding factor is (x +1).

The result of dividing the factor (x+1) from the polynomial using synthetic division is shown in the first attachment. The coefficients found mean the quotient is ...

Q(x) = x^2 -5x -14

Factoring this using any method you like gives ...

Q(x) = (x +2)(x -7)

This means the full set of zeros is {-2, -1, +7} and the factorization is ...

P(x) = (x +2)(x +1)(x -7)

_____

Additional comment

My personal favorite method of finding the zeros is to let a graphing calculator show them to me. That result is shown in the second attachment.

Does anyone know how to solve this?-example-1
Does anyone know how to solve this?-example-2
User Phayes
by
5.4k points