Question

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In ΔABC right angled at A, D and E are points on BC, C such that BC= CD and AD ⊥ BC

Answer 1

Correct Inputs :-

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

`\underline{\underline{\large\bf{Solution:-}}}\\`

`\longrightarrow` Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

`\leadsto`Median is the line segment from a vertex to the midpoint of the opposite side.

Let us Check all options one by one

• CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

• BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

• AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

• AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

• AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️