Question

A 25-foot ladder is placed against a vertical wall of a

building, with the bottom of the ladder standing on
level ground 9 feet from the base of the building. How
high up the wall does the ladder reach?

Answer 1

26.5ft

Explanation:

Consider:

AB=25 ft

BC =9 ft

AC=?ft

`(AB)^2 + (BC)^2 = (AC)^2\\25^2+ 9^2=(AC)^2\\(AC)^2= 625+81\\`

AC=√706

AC=26.5 ft

Hope this helps! :)