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1) The population of Leafy Lake starts at 3,000 and grows by 25% every year. What will the population be in 6 years?

how do I solve it

User Nal
by
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2 Answers

4 votes
X/3,000 = 25/100
100x = 3,000x25
100x = 75,000
100x/100 = 75,000/100
X = 750

750x6 = 4,500
Every year the population goes up by 750, in 6 years the population would be 4,500 people.
User Splines
by
7.8k points
0 votes

Answer:

Explanation:

Rate of increase = r = 25%

n = number of years = 6

P = Current population = 3000

Population after n years =
P*(1 + (r)/(100))^(n)


= 3000 * (1 +0.25)^(6)\\\\= 3000 * (1.25)^(6)\\\\= 3000 * 3.8\\\\= 11400=

User Miguel Madero
by
8.2k points

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